2/3x^(1/3)-5x^(2/3)/3=0

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Solution for 2/3x^(1/3)-5x^(2/3)/3=0 equation:


x in (-oo:+oo)

(2/3)*x^(1/3)-((5*x^(2/3))/3) = 0

(-5/3)*x^(2/3)+(2/3)*x^(1/3) = 0

2/3*x^(1/3)-5/3*x^(2/3) = 0

t_1 = x^(1/3)

2/3*t_1^1-5/3*t_1^2 = 0

2/3*t_1-5/3*t_1^2 = 0

DELTA = (2/3)^2-(-5/3*0*4)

DELTA = 4/9

DELTA > 0

t_1 = ((4/9)^(1/2)-2/3)/(-5/3*2) or t_1 = (-(4/9)^(1/2)-2/3)/(-5/3*2)

t_1 = 0 or t_1 = 2/5

t_1 = 0

x^(1/3)+0 = 0

x^(1/3) = 0

1*x^(1/3) = 0 // : 1

x^(1/3) = 0

x = 0

t_1 = 2/5

x^(1/3)-2/5 = 0

1*x^(1/3) = 2/5 // : 1

x^(1/3) = 2/5

x^(1/3) = 2/5 // ^ 3

x = 8/125

x in { 0, 8/125 }

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